Q:

On the moon, the acceleration due to gravity is -1.6 meters per second per second. A stone is dropped from a cliff on the moon and hits the surface of the moon 20 seconds later.a) How far did it fall?b) What was its velocity at impact?

Accepted Solution

A:
Answer:How far did it fall? -320 metersWhat was its velocity at impact? -32 m/sStep-by-step explanation:a) How far did it fall?To calculate the distance traveled by the stone we must use the following formula:[tex]d=\frac{gt^{2}}{2}[/tex]Sustituing the given values we have that:[tex]d=\frac{-1.6\times 20^{2}}{2}\\ d=\frac{-1.6\times 400}{2}\\ d=\frac{-640}{2}\\ d=-320 m[/tex]The distance traveled by the stone was -320 meters under the released pointb) What was its velocity at impact?To calculate the velocity we need to use the formula:[tex]v=gt[/tex]Sustituing the given values we have that:[tex]v=(-1.6)(20)\\v=-32 m/s[/tex]So the velocity is -32 meteres per second, the negative sign indicate that the object is going down