The coordinates of the vertices of quadrilateral ABCD are A(0, −4) , B(−4, 3) , C(3, 4) , and D(6, −1) . Drag and drop the choices into each box to correctly complete the sentences. The slope of AB¯¯¯¯¯ is , the slope of BC¯¯¯¯¯ is , the slope of CD¯¯¯¯¯ is , and the slope of AD¯¯¯¯¯ is . Quadrilateral ABCD is because .

Answer:The slope of AB is -7/4, the slope of BC is 1/7 , the slope of CD is 5/3, and the slope of AD is 2. So, Quadrilateral ABCD is neither a parallelogram nor a trapezoid because neither pair of opposite sides are parallel.Step-by-step explanation:Since, a quadrilateral having,One pair of parallel opposite sides is Trapezoid,While, having two pair of parallel opposite sides is parallelogram.Since, the slope of a line segment having the end points [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] is,[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Here, the vertices of the quadrilateral ABCD are A(0, −4) , B(−4, 3) , C(3, 4) , and D(6, −1),Slope of AB = [tex]\frac{3+4}{-4-0}=-\frac{7}{4}[/tex]Slope of BC = [tex]\frac{4-3}{3+4}=\frac{1}{7}[/tex]Slope of CD = [tex]\frac{-1-4}{6-3}=-\frac{5}{3}[/tex]Slope of AD = [tex]\frac{-1+4}{6-0}=\frac{3}{6}=2[/tex] Hence, Quadrilateral ABCD is neither a parallelogram nor a trapezoid because neither pair of opposite sides are parallel.